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Find the number of permutations of letters in the following word: SHANTARAM - Mathematics and Statistics

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Question

Find the number of permutations of letters in the following word:

SHANTARAM

Sum

Solution

In the word 'SHANTARAM', the number of letters is n = 9 of which A repeats thrice, i.e., p = 3 and rest are distinct.

∴ the number of distinct permutations of the letters

= `("n"!)/("p"!)`

= `(9!)/(3!)`

= `(9 xx 8 xx 7 xx 6 xx 5 xx 4 xx 3!)/(3!)`

= 9 × 8 × 7 × 6 × 5 × 4

= 60480.

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Permutations - Permutations When Some Objects Are Identical
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Chapter 3: Permutations and Combination - Exercise 3.4 [Page 57]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board
Chapter 3 Permutations and Combination
Exercise 3.4 | Q 1. (ii) | Page 57

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