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Question
Find the number of side of a polygon, if the sum of its interior angle is: 1440°
Sum
Solution
1440°
Let no. of. sides = n
∴ Sum of interior angles of polygon = 1440°
∴ (2n - 4) × 90° = 1440°
⇒ 2n - 4 = `(1440°)/(90°)`
⇒ 2(n - 2) = `(1440°)/(90°)`
⇒ n - 2 = `(1440°)/(2 xx 90°)`
⇒ n - 2 = 8
⇒ n = 8 + 2
⇒ n = 10
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