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Question
Find the number which bears the same ratio to `7/33` that `8/21` does to `4/9`.
Solution
Let the required number be `"x"/"y"`
Now, ratio of `8/21` to `4/9 = (8/21)/(4/9) = 8/21 xx 9/4 = 6/7`
thus we have
`("x"/"y")/(7/33) = 6/7`
⇒ `"x"/"y" = (6/7)/(7/33)`
⇒ `"x"/"y" = 6/7 xx 7/33`
⇒ `"x"/"y" = 2/11`
Hence the required number is `2/11`
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