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Maharashtra State BoardSSC (English Medium) 7th Standard

Find the perimeter and area of a garden with measures as shown in the figure alongside. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Find the perimeter and area of a garden with measures as shown in the figure alongside.

Sum

Solution

Let us mark the vertices of the given polygon as A, B, C, D, E, F, G, H, I, J, K, and L.
Perimeter of garden ABCDEFGHIJKL = sum of all the sides of polygon = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA
= 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13
= 156 m

The given figure of the garden can be broken into five squares as follows.

Now, the length of each side of each of the five squares is equal to 13 m.
Area of each square = side × side
= 13 × 13
= 169 m2
∴ Area of the five squares = 5 × areas of each square
= 5 × 169
= 845 m2
Hence, the area of the given garden is 845 m2.

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Chapter 12: Perimeter and Area - Practice Set 46 [Page 84]

APPEARS IN

Balbharati Mathematics [English] 7 Standard Maharashtra State Board
Chapter 12 Perimeter and Area
Practice Set 46 | Q 5 | Page 84
Balbharati Integrated 7 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.4 Perimeter and Area
Practice Set 46 | Q 5. | Page 62
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