Advertisements
Advertisements
Question
Find the probability distribution of the number of successes in two toves of a die where a success is define as:- Six appeared on at least one die.
Options
`1/9`
11
`25/36`
`11/36`
MCQ
Solution
`11/36`
Explanation:
Zero success = 6 does not appear on any die.
= 1, 2, 3, 4, 5 appear on both die
∴ Number of such cases = 25
P(0) = `25/36`
(1) Success ⇒ 6 appears on one dice and 1, 2, 3, 4, 5 appears
(2) Success ⇒ 6 appears on both dice (6, 6).
Number of such cases = 1.
Number of cores wl:ten there is at least one 'six' appears = 10 + 1 = 11
∴ Probability of getting at least 1 six = `11/36`.
∴ Pobability distribution is
X | 0 | 1 |
P(x) | `25/36` | `11/36` |
shaalaa.com
Is there an error in this question or solution?