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Maharashtra State BoardSSC (English Medium) 9th Standard

Find the reduced form of the ratio of the first quantity to second quantity. ₹ 14, ₹ 12. 40 paise - Algebra

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Question

Find the reduced form of the ratio of the first quantity to second quantity.

₹ 14, ₹ 12. 40 paise

Sum

Solution

14 rupees = 1400 p

12 rupees 40 paise = 1200 + 40 = 1240 p

∴ 14 rupees : 12 rupees 40 paise

= 1400 p : 1240 p

= `(1400 ÷ 40) /(1240 ÷ 40)`

= `35/31`

= 35 : 31              ...(HCF of 1400 and 1240 = 40)

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Properties of Ratio
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Chapter 4: Ratio and Proportion - Practice Set 4.1 [Page 61]

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Balbharati Algebra (Mathematics 1) [English] 9 Standard Maharashtra State Board
Chapter 4 Ratio and Proportion
Practice Set 4.1 | Q (2) (ii) | Page 61
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