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Question
Find the smallest number by which of the following number must be divided to obtain a perfect cube.
128
Solution
| 2 | 128 |
| 2 | 64 |
| 2 | 32 |
| 2 | 16 |
| 2 | 8 |
| 2 | 4 |
| 2 | 2 |
| 1 |
128 = 2 × 2 × 2 × 2 × 2 × 2 × 2
Here, one 2 is left, which is not in a triplet.
If we divide 128 by 2, then it will become a perfect cube.
Thus, 128 ÷ 2
= 64
= 2 × 2 × 2 × 2 × 2 × 2 is a perfect cube.
Hence, the smallest number by which 128 should be divided to make it a perfect cube is 2.
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