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Find the Smallest Number that is Completely Divisible by 28 and 42. - Mathematics

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Question

Find the smallest number that is completely divisible by 28 and 42.

Sum

Solution

We know that the least number which is divisible by 28 and 42 is their L.C.M.

2 28, 42
7 14, 21
  2, 3

L.C.M. of 28 and 42 = 2 × 2 × 3 × 7 = 84

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Division Method for HCF and LCM
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Chapter 8: HCF and LCM - Revision Exercise

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Selina Mathematics [English] Class 6
Chapter 8 HCF and LCM
Revision Exercise | Q 6.1
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