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Question
Find the sum of 3x + 4xy − y2, xy − 4x + 2y2 and 3y2 − xy + 6x.
Solution
(3x + 4xy − y2) + (xy − 4x + 2y2) + (3y2 − xy + 6x)
= 3x + 4xy − y2 + xy − 4x + 2y2 + 3y2 − xy + 6x
= 3x + 6x − 4x + 4xy + xy − xy + 2y2 + 3y2 − y2
= 9x − 4x + 5xy − xy + 5y2 − y2
= 5x + 4xy + 4y2
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