Advertisements
Advertisements
Question
Find the value of Dx for the equation 4x + 3y = 19 and 4x − 3y = −11
Options
24
0
− 24
108
Solution
− 24
Explanation:
Here, a1 = 4, b1 = 3, c1 = 19
a2 = 4, b2 = -3, c2 = -11
∴ Dx = `|(c_1, b_1),(c_2, b_2)| = |(19, 3),(-11, -3)|`
= -57 + 33
= -24
APPEARS IN
RELATED QUESTIONS
Find the value of determinant: `|[4,-2],[3,1]|`
If the value of determinant `|[m,2],[-5,7]|`is 31, find the value of m
Choose correct alternative for the following question.
To draw graph of 4x + 5y = 19, Find y when x = 1.
Find the value of `|(5,3),(-7,-4)|`.
Find the value of the following determinant.
`|(5, -2), (-3, 1)|`
Find the value of the following determinant.
Select the correct alternative and write it.
What is the degree of the determinant `|[a ,b],[c,d]|`
Find the value of the determinant: `|(-3,8),(6,0)|`
Find the value of the determinant `[(5,2),(7,4)]`
`|(3, 5),(2, x)|` = 2 ∴ x = ______
If Dx = 24 and x = – 3, then find the value of D
Solve the following to find the value of following determinant.
`|(3, -2),(4, 5)| = 3 xx square - square xx 4 = square + 8 = square`
Find the value of `|(5, 2),(0, -1)|`
For the equations y + 2x = 19 and 2x – 3y = − 3, find the value of D.
Using the determinants given below form two linear equations and solve them.
D = `|(5, 7),(2, -3)|`, Dy = `|(5, 4),(2, -10)|`
