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Question
Find the value of: `"log_(1/2)16`
Sum
Solution
`"log_(1/2)16`
Let `"log_(1/2)16` = x
⇒ 16 = `(1/2)^x`
⇒ 2-x = 24
⇒ x = -4
∴ -x = 4.
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Interchanging Logarithmic and Exponential Forms - Logarithmic to Exponential
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