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Question
Find the value of x° in the following figure:
Sum
Solution
∠OPN = ∠ONP ...(ON and OP are the radius of the circle)
= 90°
In ΔOPN
∠PON + ∠ONP + ∠NPO = 180° ...(Sum of the angles of a triangle)
70° + x° + x° = 180°
2x° + 70° = 180°
2x = 180° – 70°
2x = 110°
x = `(110^circ)/2`
= 55°
The value of x = 55°
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Angle at the Centre and the Circumference
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Chapter 4: Geometry - Exercise 4.3 [Page 170]
