Advertisements
Advertisements
Question
Find the values of following polynomials at m = 1, n = –1 and p = 2:
mn + np + pm
Solution
Given, m = 1, n = –1 and p = 2
So, putting m = 1, n = –1 and p = 2 in the given expressions, we get
mn + np + pm = (1)(–1) + (–1)(2) + (2)(1)
= –1 – 2 + 2
= –1
APPEARS IN
RELATED QUESTIONS
Classify the following polynomials as monomials, binomials, trinomials. Which polynomials do not fit in any of these three categories?
x + y, 1000, x + x2 + x3 + x4, 7 + y + 5x, 2y − 3y2, 2y − 3y2 + 4y3, 5x − 4y + 3xy, 4z − 15z2, ab + bc + cd + da, pqr, p2q + pq2, 2p + 2q
Classify into monomials, binomials and trinomials.
ab − a − b
Classify the following polynomial as monomial, binomial, trinomial. Which polynomial do not fit in any category?
2y − 3y2 + 4y3
Find the product of 3(x – 5) × 2(x – 1)
The product of a monomial and a binomial is a ______.
The product of two polynomials is a ______.
When we subtract a monomial from a trinomial, then answer can be a polynomial.
Find the values of following polynomials at m = 1, n = –1 and p = 2:
m2n2 + n2p2 + p2m2
