Question

Find the wavelength and wave number of the first member of the Balmer series in Hydrogen spectrum. (`R =1.097xx10^7m^(-1)`)

Answer 1

`1/λ=R[1/p^2-1/n^2]`

`1/λ=R[1/4-1/9]`

`1/λ=R[5/36]`

`λ=36/(5R)`

`=36/5xx1/(1.097xx10^7)`

`=36/5.485xx10^(-7)`

`=6.563xx10^(-7)m`

λ = 6563 A

Wave number(`barv`)=`1/λ`

`=1/(6.563xx10^(-7))`

`= 1.524 xx10^6m^(-1)`