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Question
Find the time required to liberate 1.0 litre of hydrogen at STP in an electrolytic cell by a current of 5.0 A.
Sum
Solution
Let the required time be t.
Mass of 1 litre hydrogen,
\[m = \frac{2}{22 . 4} g\]
Using the formula, m = Zit, we get:-
\[\frac{2}{22 . 4} = \frac{1 \times 5 \times t}{96500}\]
\[ \Rightarrow t = \frac{2 \times 96500}{22 . 4 \times 5}\]
\[ \Rightarrow t = 1723 . 21 s = 28 . 7\text{ minutes} \approx 29\text{ minutes}\]
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