Advertisements
Advertisements
Question
Find the value of the discriminant in the following quadratic equation :
x2 +2x+4=0
Solution
x2 +2x+4=0
Discriminant = b2 - 4ac
= (2)2 - 4(1)(4)
= 4 -16
= - 12
APPEARS IN
RELATED QUESTIONS
Find the values of k for which the roots are real and equal in each of the following equation:
(2k + 1)x2 + 2(k + 3)x + (k + 5) = 0
Find the values of k for which the roots are real and equal in each of the following equation:
kx(x - 2) + 6 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
x2 - 4kx + k = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx + 3 = 0
Determine the nature of the roots of the following quadratic equation :
2x2 + x-1=0
If one root of the equation 2x² – px + 4 = 0 is 2, find the other root. Also find the value of p.
If the ratio of the roots of the equation
lx2 + nx + n = 0 is p: q, Prove that
`sqrt(p/q) + sqrt(q/p) + sqrt(n/l) = 0.`
Discuss the nature of the roots of the following equation: 3x2 – 7x + 8 = 0
Every quadratic equation has exactly one root.
Find the value of ‘c’ for which the quadratic equation
(c + 1) x2 - 6(c + 1) x + 3(c + 9) = 0; c ≠ - 1
has real and equal roots.
