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Question
Find the value of k for which each of the following system of equations have no solution :
2x + ky = 11
5x − 7y = 5
Solution
The given system of equation is
2x + ky - 11 =0
5x − 7y - 5 = 0
The system of equation is of the form
`a_1x + b_1y + c_1 = 0`
`a_2x + b_2y + c_2 = 0`
Where, `a_1 = 2,b_1 = k, c_1 = -11`
And `a_2 = 5, b_2 = -7, c_2 = -5`
For a unique solution, we must have
`a_1/a_2 - b_1/b_2 != c_1/c_2`
`=> 2/5 = k/(-7) != (-11)/(-5)`
Now
`2/5 = k/(-7)`
`=> 2 xx (-7) = 5k`
`=> 5k = -14`
`=> k = (-14)/5`
Cleary for `(-14)/5` we have `k/(-7) != (-11)/(-5)`
Hence, the given system of equation will have no solution if `k = (-14)/5`
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