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Question
Find the value of k for which the following system of equations has a unique solution:
4x + ky + 8 = 0
2x + 2y + 2 = 0
Solution
Here `a_1 = 4, a_2 = k, b_1 = 2, b_2 = 2``
Now for the given pair to have a unique solution `a_1/a_2 != b_1/b_2`
i.e `4/2 != k/2`
i.e `k != 4`
Therefore, for all values of k, except 4, the given pair of equations will have a unique solution.
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