Advertisements
Advertisements
Question
Find whether the first polynomial is a factor of the second.
x + 1, 2x2 + 5x + 4
Solution
\[ \frac{2 x^2 + 5x + 4}{x + 1}\]
\[ = \frac{2x(x + 1) + 3(x + 1) + 1}{x + 1}\]
\[ = \frac{(x + 1)(2x + 3) + 1}{(x + 1)}\]
\[ = (2x + 3) + \frac{1}{x + 1}\]
\[ \because \text{Remainder} = 1\]
\[\text{Therefore, (x + 1) is not a factor of}\ 2 x^2 + 5x + 4\]
APPEARS IN
RELATED QUESTIONS
Divide the given polynomial by the given monomial.
(5x2 − 6x) ÷ 3x
Write the degree of each of the following polynomials.
2x + x2 − 8
Write each of the following polynomials in the standard form. Also, write their degree.
a2 + 4 + 5a6
Divide x2 + 7x + 12 by x + 4.
Divide 4y2 + 3y +\[\frac{1}{2}\] by 2y + 1.
Divide 14x2 − 53x + 45 by 7x − 9.
Divide 14x3 − 5x2 + 9x − 1 by 2x − 1 and find the quotient and remainder
Divide the first polynomial by the second in each of the following. Also, write the quotient and remainder:
3x2 + 4x + 5, x − 2
Find whether the first polynomial is a factor of the second.
4 − z, 3z2 − 13z + 4
Simplify `(14"p"^5"q"^3)/(2"p"^2"q") - (12"p"^3"q"^4)/(3"q"^2)`