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Question
Find x, if `"g"(x)` = 0 where `"g"(x)` = 6x2 + x − 2
Solution
`"g"(x)` = 6x2 + x − 2
`"g"(x)` = 0
∴ 6x2 + x – 2 = 0
∴ 6x2 + 4x − 3x − 2 = 0
∴ 2x(3x + 2) − 1(3x + 2) = 0
∴ (2x – 1) (3x + 2) = 0
∴ 2x – 1 = 0 or 3x + 2 = 0
∴ x = `1/2` or x = – `2/3`
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