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Question
Following data gives the coded price (X) and demand (Y) of a commodity.
Price | 5 | 7 | 9 | 8 | 10 | 7 | 9 | 8 | 5 | 11 | 11 | 10 | 2 | 3 | 9 |
Demand | 9 | 15 | 13 | 15 | 14 | 10 | 11 | 14 | 10 | 14 | 6 | 14 | 15 | 11 | 12 |
Price | 2 | 4 | 3 | 14 | 6 | 10 | 7 | 15 | 8 | 6 | 5 | 6 | 11 | 14 | 15 |
Demand | 6 | 11 | 8 | 11 | 10 | 15 | 9 | 15 | 13 | 9 | 14 | 10 | 7 | 5 | 6 |
Classify the data by taking classes 0 – 4, 5 – 9, etc. for X and 5 – 8, 9 – 12, etc. for Y. Also find marginal frequency distribution of X and Y.
Solution
Given,
X = coded price
Y= demand
Bivariate frequency table can be prepared by taking class intervals 0 – 4, 5 – 9,…etc for X and 5 – 8, 9 – 12,… etc for Y.
Bivariate frequency distribution is as follows:
Demand (Y)/Coded price (X) | 0 – 4 | 5 – 9 | 10 – 14 | 15 – 19 | Total (fy) |
5 – 8 | II (2) | III (3) | I (1) | 6 | |
9 – 12 | II (2) | IIII IIII (9) | I (1) | – | 12 |
13 – 16 | I (1) | IIII I (6) | IIII (4) | I (1) | 12 |
Total (fx) | 5 | 15 | 2 | 30 |
Marginal frequency distribution of X:
X | 0 – 4 | 5 – 9 | 10 – 14 | 15 – 19 | Total |
Frequency | 5 | 15 | 8 | 2 | 30 |
Marginal frequency distribution of Y:
Y | 5 – 8 | 9 – 12 | 13 – 16 | Total |
Frequency | 6 | 12 | 12 | 30 |
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