Question

Following QN ∴ 14, the radiation force on the roof will be

Options

• 8.53 × 10^–5N

• 2.3 × 10³N

• 1.33 × 10^–3N

• 5.33 × 10^–4N

Answer 1

5.33 × 10^–4N

Explanation:

The radiation force = `"Total power"/"Velocity of light"`

= `(1.6 xx 10^5)/(3 xx 10^8)`

= 5.33 × 10^–4N