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Question
For a frequency distribution Q3 – Q2 = 90 And Q2 – Q1 = 120, find Skb.
Solution
Given, Q2 – Q1 = 120, Q3 – Q2 = 90
Bowley’s co-efficient of skewness,
∴ Skb = `("Q"_3+"Q"_1-2"Q"_2)/("Q"_3-"Q"_1)`
= `("Q"_3-"Q"_2-"Q"_2+"Q"_1)/("Q"_3-"Q"_2+"Q"_2-"Q"_1)`
= `(("Q"_3-"Q"_2)-("Q"_2-"Q"_1))/(("Q"_3-"Q"_2)+("Q"_2-"Q"_1)`
= `(90 - 120)/(90 + 120)`
= `(-30)/(210)`
= `(-1)/7`
∴ Skb = − 0.1429
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