English

For a hypothetical reaction A+B⟶C, it is found that doubling the concentration of A increases the rate by 8 times and doubling the concentration of B increases the rate by 4 times. -

Advertisements
Advertisements

Question

For a hypothetical reaction \[\ce{A + B -> C}\], it is found that doubling the concentration of A increases the rate by 8 times and doubling the concentration of B increases the rate by 4 times. The overall order of the reaction is ____________.

Options

  • 4

  • 2

  • 3

  • 5

MCQ
Fill in the Blanks

Solution

For a hypothetical reaction \[\ce{A + B -> C}\], it is found that doubling the concentration of A increases the rate by 8 times and doubling the concentration of B increases the rate by 4 times. The overall order of the reaction is 5.

Explanation:

Let the rate of given reaction be:

(rate)1 = k [A]x [B]y

Doubling the concentration of A increases the rate by 8.

∴ (rate)2 = k [2A]x [B]y = 2x k [A]x [B]y

∴ (rate)2 = 2x × (rate)1

`("rate")_2/("rate")_1` = 2x

8 = 2x

∴ x = 3

Doubling the concentration of B increases the rate by 4.

(rate)3 = k [A]x [2B]y

(rate)3 = 2y k [A]x [B]y

∴ (rate)3 = 2y (rate)1

`("rate")_3/("rate")_1` = 2y

4 = 2y

∴ y = 2

∴ Overall order = x + y = 3 + 2 = 5

shaalaa.com
Rate of Reaction and Reactant Concentration
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×