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Question
For a photocell, work function is 'W0' and stopping potential is 'v'. The wavelength of the incident radiation is (h =Planck's constant, C = velocity of light, e = charge of electron) ____________.
Options
`("hc")/("W"_0 - "eV")`
`("h"^2"c"^2)/("W"_0 + "eV")`
`("h"^2"c"^2)/("W"_0 + "e"^2"V")`
`("hc")/("W"_0 + "eV")`
MCQ
Fill in the Blanks
Solution
For a photocell, work function is 'W0' and stopping potential is 'v'. The wavelength of the incident radiation is `("hc")/("W"_0 + "eV")`.
Explanation:
We have the relation:
`"eV" = "hC"/lambda - "W"_0`
`therefore "hc"/lambda = "W"_0 + "eV"`
`therefore lambda = "hc"/("W"_0 + "eV")`
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