Question

For a reaction, given below is the graph of ln k vs `1/"T"`. The activation energy for the reaction is equal to ______ cal mol^-1. (Nearest integer) (Given : R = 2 cal K^-1 mol^-1)

Options

• 5

• 8

• 2

• 10

Answer 1

For a reaction, given below is the graph of ln k vs `1/"T"`. The activation energy for the reaction is equal to 8 cal mol^-1. 

Explanation:

k = `"Ae"^(-"E"_"a"//"RT")`

Taking ln both sides;

`ln "k" = (- "E"_"a")/"RT" + ln "A"`

y = mx + c

Slope = `"E"_"a"/"R" = 20/5`

E_a = 4R = 8 cal/mol