Question

For a reversible reaction forward and backward rate constant respectively are 2.5 × 10^–4 and 7.5 × 10^–4. What is the value of equilibrium constant?

Options

• 3

• 0.33

• 1

• 2.5

Answer 1

0.33

Explanation:

K = `k_f/k_b = (2.5 xx 10^-4)/(7.5 xx 10^-4) = 1/3` = 0.33