Question

For a transistor,  α_dc and β_dc are the current ratios, then the value of `(beta_"dc"-delta_"dc")/(alpha_"dc".beta_"dc")` 

Options

• 1

• 1.5

• 2

• 2.5

Answer 1

1

Explanation:

As we know, β_dc = `alpha_"dc"/(1-alpha_"dc")`

∴ `(1-alpha_"dc")=alpha_"dc"/beta_"dc"`       ...(i)

Also, `(beta_"dc"-alpha_"dc")/(alpha_"dc".beta_"dc")=(beta_"dc"(1-alpha_"dc"/beta_"dc"))/(alpha_"dc".beta_"dc")`

From equation (i)

`(1-alpha_"dc"/beta_"dc")/(alpha_"dc")=(1-(1-alpha_"dc"))/alpha_"dc"`

= `(1-1+alpha_"dc")/alpha_"dc"`

= 1