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Question
For an isothermal expansion of a perfect gas, the value of `(Delta "P")/"P"` is equal to ____________.
Options
`-gamma^(1//2) (Delta"V")/"V"`
`-(Delta"V")/"V"`
`-gamma (Delta"V")/"V"`
`-gamma^2 (Delta"V")/"V"`
MCQ
Fill in the Blanks
Solution
For an isothermal expansion of a perfect gas, the value of `(Delta "P")/"P"` is equal to `-(Delta"V")/"V"`.
Explanation:
Differentiating the equation, PV = constant
`"P" Delta "V" + "V" Delta "P" = 0 Rightarrow (Delta "P")/"P" = - (Delta "V")/"V"`
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Thermodynamic Process
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