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Question
For an L.P.P. the objective function is Z = 4x + 3y and the feasible region determined by a set of constraints (linear inequations) is shown in the graph.
Which one of the following statements is true?
Options
Maximum value of Z is at R.
Maximum value of Z is at Q.
Value of Z at R is less than the value at P.
Value of Z at Q is less than the value at R.
MCQ
Graph
Solution
Maximum value of Z is at Q.
Explanation:
Corner Points of Feasible Region |
Value of z = (z = 4x + 3y) |
O(0, 0) | Z = 4(0) + 3(0) = 0 |
P(0, 40) | Z = 4(0) + 3(40) = 120 |
Q(30, 20) | Z = 4(30) + 3(20) = 180 (Maximum) |
R(40, 0) | Z = 4(40) + 3(0) = 160 |
Thus, Maximum value of z is at Q, which is 180.
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