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For the differential equation, find the general solution: dydx+y=1(y≠1) - Mathematics

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Question

For the differential equation, find the general solution:

`dy/dx + y = 1(y != 1)`

Sum

Solution

`dy/dx + y = 1`

⇒ `dy/dx = - (y - 1)`

⇒ `dy/(y - 1) = - dx`                     ....(1)

Integrating (1) both sides, we get

⇒ `intdy/(y - 1) = - intdx`

⇒ log (y - 1) = -x + C1

⇒ y - 1 = e-x+C1

⇒ y = 1 + e-x . eC1

Hence, y = 1 + Ce-x, which is the required solution

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Chapter 9: Differential Equations - Exercise 9.4 [Page 396]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 9 Differential Equations
Exercise 9.4 | Q 3 | Page 396

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