Advertisements
Advertisements
Question
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
Solution
Using law of exponents, am × an = (a)m + n ...[∵ a is non-zero integer]
Hook-up machine's work = (0.5)2 × (0.5)3 = (0.5)5 ...[∵ am × an = am + n]
So, (×(0.5)5) machine can for the same work.
Diagram of single ×(0.5)5 machine.
APPEARS IN
RELATED QUESTIONS
Simplify and write the answer in the exponential form.
`(- 3)^4 xx (5/3)^4`
Find the value [4–1 + 3–1 + 6–2]–1 = ______.
The value of [2–1 × 3–1]–1 is ______.
`a^m = 1/a^-m`
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do you think the value of 60 is?
Find a single machine that will do the same job as the given hook-up.
a (× 24) machine followed by `(xx (1/2)^2)` machine.
Find a single repeater machine that will do the same work as hook-up.
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.
Simplify:
`((9)^3 xx 27 xx t^4)/((3)^-2 xx (3)^4 xx t^2)`
