Question

For the following distribution function F(x) of a rv.x.

x	1	2	3	4	5	6
F(x)	0.2	0.37	0.48	0.62	0.85	1

P(3 < x < 5) =

Options

• 0.48

• 0.37

• 0.27

• 1.47

Answer 1

0.37

Explanation:

p(3 < x ≤ 5) = p(x = 4) + p(x = 5)

= (0.62 – 0.48) + (0.85 – 0.62)

= 0.14 + 0.23

= 0.37