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For the following number, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained. 768 - Mathematics

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Question

For the following number, find the smallest whole number by which it should be multiplied so as to get a perfect square number. Also find the square root of the square number so obtained.

768

Sum

Solution

768 can be factorised as follows:

2 768
2 384
2 192
2 96
2 48
2 24
2 12
3 6
  13

768 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3

Here, prime factor 3 does not have its pair. If 3 gets a pair, then the number will become a perfect square. Therefore, 768 has to be multiplied with 3 to obtain a perfect square.

Therefore, 768 × 3 = 2304 is a perfect square.

768 × 3 = 2304 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

∴ `sqrt(2304)` = 2 × 2 × 2 × 2 × 3 = 48

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Chapter 6: Squares and Square Roots - Exercise 6.3 [Page 102]

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NCERT Mathematics [English] Class 8
Chapter 6 Squares and Square Roots
Exercise 6.3 | Q 5.6 | Page 102

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