Question

For the reaction \[\ce{2NO2 + F2 -> 2NO2F}\], following mechanism has been provided:

\[\ce{NO2 + F2 ->[slow] NO2F + F}\]

\[\ce{NO2 + F ->[fast] NO2F}\]

The rate expression of the above reaction can be written as:

Options

• r = k [NO₂]² [F₂]

• r = k [NO₂] [F₂]

• r = k [NO₂] [F]

• r = k [F₂]

Answer 1

r = k [NO₂] [F₂]

Explanation:

The rate of the reaction depends on the first step since it is a slow step. The slow step is first order with respect to each of the reactants NO₂ and F₂. Hence, the rate expression is r = k [NO₂] [F₂]