Question

For the reaction \[\ce{4NH3 + 5O2 -> 4NO + 6H2O}\], the rate of disappearance of NH₃ is 3.6 × 10^-3 M/s. What is the rate of formation of water?

Options

• 6.0 × 10^-4 M/s

• 5.4 × 10^-3 M/s

• 3.6 × 10^-3 M/s

• 4.0 × 10⁴ M/s

Answer 1

5.4 × 10^-3 M/s

Explanation:

\[\ce{4NH3 + 5O2 -> 4NO + 6H2O}\]

Rate of reaction = `- 1/4 ("d"["NH"_3])/"dt" = - 1/5 ("d"["O"_2])/"dt" = 1/4 ("d"["NO"])/"dt" = 1/6 ("d"["H"_2"O"])/"dt"`

∴ Rate of formation of water, `("d"["H"_2"O"])/"dt" = 6/4 ("d"["NH"_3])/"dt"`

`= 6/4 xx 3.6 xx 10^-3`

= 5.4 × 10^-3 M/s