Question

For the reaction \[\ce{A -> B}\], the rate increases by a factor of 2.25 when the concentration of A is increased by 1.5. What is the order of the reaction?

Options

• 3

• 0

• 2

• 1

Answer 1

2

Explanation:

The rate law is rate = k[Ar]^x .......(i)

When the concentration of A is increased by 1.5, the rate increases by a factor of 2.25

∴ 2.25 rate = k[1.5 A]^x ....(ii)

Divide (ii) by (i)

∴ `(2.25  "rate")/"rate" = ("k"[1.5  "A"]^"x")/("k"["A"]^"x")`

2.25 = (1.5)^x

(1.5)² = (1.5)^x

∴ x = 2