Question

For the reaction, \[\ce{N2(g) + 3H2(g) -> 2NH3(g); \Delta H}\] is equal to ______.

Options

• Δ U + 2RT

• Δ U + RT

• Δ U - 2RT

• Δ U + RT

Answer 1

For the reaction, \[\ce{N2(g) + 3H2(g) -> 2NH3(g); \Delta H}\] is equal to Δ U - 2RT.

Explanation:

For the reaction,

\[\ce{N2(g) + 3H2(g) -> 2NH3(g)}\]

Δ H is equal to Δ U - 2RT

∵ Δ H = Δ U + Δ nRT

For the given reaction,

Δ n, is the difference between the number of moles of product and the number of moles of reactants.

Δ n = (2 - 4) = - 2

Hence, Δ H = Δ U - 2RT