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Question
For the reaction, \[\ce{N_{2(g)} + 3H_{2(g)} -> 2NH_{3(g)}}\], ΔH is equal to ______.
Options
ΔU - RT
ΔU + 2RT
ΔU + RT
ΔU - 2RT
MCQ
Fill in the Blanks
Solution
For the reaction, \[\ce{N_{2(g)} + 3H_{2(g)} -> 2NH_{3(g)}}\], ΔH is equal to ΔU - 2RT.
Explanation:
\[\ce{N_{2(g)} + 3H_{2(g)} -> 2NH_{3(g)}}\]
∴ Δn = 2 - 4 = - 2
∴ ΔH = ΔU + Δn RT = ΔU - 2RT
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Enthalpy (H)
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