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Question
Force acting on a particle moving in a straight line varies with the velocity of the particle v as F = `K/v`, where K is a constant. The work done by this force in time t is
Options
`K/v^2 t`
`(2K)/v^2 t`
Kt
2Kt
MCQ
Solution
Kt
Explanation:
F = `K/v`
∴ W = Fs cos θ
∴ W = `K/v s` ......(∵ θ = 0°)
But velocity (v) = `("displacement" (s))/("time" (t))`
∴ W = `K xx t/s xx s`
∴ W = Kt
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