Question

Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each.

Name	Distance covered (km)
Seema	${\displaystyle \frac{1}{25}}$
Nancy	${\displaystyle \frac{1}{32}}$
Megha	${\displaystyle \frac{1}{40}}$
Soni	${\displaystyle \frac{1}{20}}$

Who walked farther, Nancy or Megha?

Answer 1

We have, ${\displaystyle \frac{1}{25},\frac{1}{32},\frac{1}{40},\frac{1}{20}}$

First, we convert the numbers as like denominators.

Taking LCM of 25, 32, 40 and 20 = ${\displaystyle 2\times 2\times 2\times 5\times 5\times 4}$ = 800

We get ${\displaystyle \frac{1}{25}=\frac{1\times 32}{25\times 32}=\frac{32}{800}}$,

${\displaystyle \frac{1}{32}=\frac{1\times 25}{32\times 25}=\frac{25}{800}}$,

${\displaystyle \frac{1}{40}=\frac{1\times 20}{40\times 20}=\frac{20}{800}}$

And ${\displaystyle \frac{1}{20}=\frac{1\times 40}{20\times 40}=\frac{40}{800}}$

Clearly, Nancy walked farther than Megha.