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Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each. Name Distance covered (km) Seema 125 Nancy 132 Megha 140 Soni 120 -

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Question

Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each.

Name Distance covered (km)
Seema `1/25`
Nancy `1/32`
Megha `1/40`
Soni `1/20`

How farther did Soni hop than Nancy?

Sum

Solution

We have, `1/25, 1/32, 1/40, 1/20`

First, we convert the numbers as like denominators.

Taking LCM of 25, 32, 40 and 20 = 2 × 2 × 2 × 5 × 5 × 4 = 800

We get

2 25, 32, 40, 20
2 25, 16, 20, 10
2 25, 8, 10, 5
5 25, 4, 5, 5
  5, 4, 1, 1

`1/25 = (1 xx 32)/(25 xx 32) = 32/800`,

`1/32 = (1 xx 25)/(32 xx 25) = 25/800`,

`1/40 = (1 xx 20)/(40 xx 20) = 20/800`

And `1/20 = (1 xx 40)/(20 xx 40) = 40/800`

Soni hop more than Nancy = `40/800 - 25/800`

= `(40 - 25)/800`

= `15/800`

= `3/160` km

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