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Question
Four particles each of mass 'M' are placed at corners of a square of side 'L'. The radius of gyration of the system about an axis perpendicular to the square and passing through its centre is ______.
Options
`L/sqrt2`
`L/sqrt8`
`L/sqrt5`
`L/sqrt3`
MCQ
Fill in the Blanks
Solution
Four particles each of mass 'M' are placed at corners of a square of side 'L'. The radius of gyration of the system about an axis perpendicular to the square and passing through its centre is `underline(L/sqrt2)`.
Explanation:
The length of the diagonal of the square `=sqrt2L`
Half of the diagonal `=(sqrt2L)/2=L/sqrt2`
Moment of inertia of the system about an axis perpendicular to the square and passing through its centre is
`I=4"m"(L/sqrt2)^2=2ML^2`
If k is the radius of gyration
then Mk2 = 2ML2
∴ k `=sqrt2 L`
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Radius of Gyration
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