Advertisements
Advertisements
Question
From the displacement-time graph of a cyclist given below in the Figure, find The average velocity in the first 4 s.
Solution
Displacement in first 4s = 10 m
Therefore, the average velocity = `"Displacement"/"time"`
= `(10/4)` m/s
= 2.5 m/s-1
APPEARS IN
RELATED QUESTIONS
Give one example of a motion where an object does not change its speed but its direction of motion changes continuously.
Write the formula to calculate the speed of a body moving along a circular path. Give the meaning of each symbol which occurs in it.
One of the following is not a vector quantity. This one is :
Give one example of following motion :
Uniform velocity
Figure shows the displacement of a body at different times .
Calculate the velocity of the body as it moves for time interval :
(i) 0 to 5 s,
(ii) 5 s to 7 s
(iii) 7 s to 9 s.
Figure shows the displacement of a body at different times .
Calculate the average velocity during the time interval 5 s to 9 s ,
[Hint : From 5 s to 9 s , displacement = 7 m - 3m = 4m]
What is the relation between distance and time when the body is moving with variable velocity?
Which of the following figures (Fig. 8.3) represents uniform motion of a moving object correctly?
A motorcyclist drives from A to B with a uniform speed of 30 km h–1 and returns back with a speed of 20 km h–1. Find its average speed.