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Question
From the railway station I took a rickshaw to go home. It is decided that I have to pay ₹ X for the first kilometre and for each kilometre ₹ Y for the next. For 10 kilometres the fare is ₹ 40 and for 16 kilometres fare is ₹ 58. Find the fare for the first kilometre
Solution
I pay ₹ X for the first kilometre and for each kilometre ₹ Y for the next.
For 10 kilometres, the fare will be ₹ X + 9Y.
For 16 kilometres, the fare will be ₹ X + 15Y.
For 10 kilometres, the fare is ₹ 40.
∴ X + 9Y = 40 ......(i)
For 16 kilometres, the fare is ₹ 58.
X + 15Y = 58 ......(ii)
Subtracting equation (i) from (ii), we get
X + 15Y = 58
X + 9Y = 40
− − −
6Y = 18
∴ Y = `18/6` = 3
Substituting Y = 3 in equation (i), we get
X + 9(3) = 40
∴ X + 27 = 40
∴ X = 40 – 27 = 13
∴ The fare for the first kilometre is ₹ 13.
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In a factory the ratio of salary of skilled and unskilled workers is 5 : 3. Total salary of one day of both of them is Rs 720. Find daily wages of skilled and unskilled workers.
The sum of a two digit number and the number obtained by reversing its digits is 121. Find the number if its units place digit is greater than the tens place digit by 7.
I held a number 75 in my mind. Write any condition showing the relation between their digits. Write the condition showing the relation between the number and the number obtained by interchanging the digits
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x = `(square xx 100)/square`
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Hence, Roshan get ₹ `square` as monthly Salary.
