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Question
From the top of a building 60 m high, the angles of depression of the top and bottom of the vertical lamp post are observed to be 30° and 60° respectively.
- Find the horizontal distance between the building and the lamp post.
- Find the distance between the tops of the building and the lamp post.
Sum
Solution
Let the horizontal· distance between the building and lamp post is BC
i. In ΔABC, ∠B = 90°
`tan C = (AB)/(BC)` .... `[∵ tan theta = P/B]`
`tan 60"°" = 60/(BC)`
⇒ `sqrt3 = 60/(BC)`
BC = `60/sqrt3 xx sqrt3/sqrt3`
⇒ BC = `(60sqrt3)/3`
BC = `20sqrt3`
ii. ED = BC = `20sqrt3` m ...(Distance between two parallel lines)
In ΔAED, ∠AED = 90°
`cos D = (ED)/(AD)` ...`[∵ cos theta = B/H]`
`cos 30"°" = (20sqrt3)/(AD)`
⇒ `sqrt3/2 = (20sqrt3)/(AD)`
AD = 40m
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