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Question
Given `1/a` = 0.5 CM–1, R = 50 ohm, N = 1.0 then equivalent conductance of electrolytic cell is
Options
10 ohm–1 cm2 (gm equir–1)
20 ohm–1 cm2 (gm equir–1)
300 ohm–1 cm2 (gm equir–1)
100 ohm–1 cm2 (gm equir–1)
MCQ
Solution
10 ohm–1 cm2 (gm equir–1)
Explanation:
`K = 1/a xx 1/R = (0.5 CM - 1) xx (1/50 ohm^-1)`
= 0.01 ohm–1 cm–1
E = `(K xx 100)/N = ((0.01 ohm^-1 cm^-1) xx (1000 cm^3))/(1 gm "equivalemt")`
= `10 ohm^-1 cm^2 g/"equivalent"`
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