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Given A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈ A, y ∈ A}. Find the ordered pairs which satisfy the conditions given below: x + y > 8 - Mathematics

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Question

Given A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈ A, y ∈ A}. Find the ordered pairs which satisfy the conditions given below:

x + y > 8

Sum

Solution

A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈ A, y ∈ A}

x + y > 8

So, we find the ordered pair such that x + y > 8

Where x and y belongs to set A = {1, 2, 3, 4, 5}

1 + 1 = 2 < 8

1 + 2 = 3 < 8

1 + 3 = 4 < 8

1 + 4 = 5 < 8

1 + 5 = 6 < 8

2 + 1 = 3 < 8

2 + 2 = 4 < 8

2 + 3 = 5 < 8

2 + 4 = 6 < 8

2 + 5 = 7 < 8

3 + 1 = 4 < 8

3 + 2 = 5 < 8

3 + 3 = 6 < 8

3 + 4 = 7 < 8

3 + 5 = 8

4 + 1 = < 8

4 + 2 = 6 < 8

4 + 3 = 7 < 8

4 + 4 = 8

4 + 5 = 9 > 8

So one of the ordered pairs is (4, 5)

5 + 1 = 6 < 8

5 + 2 = 7 < 8

5 + 3 = 8

5 + 4 = 9>8

So one of the ordered pairs is (5, 4)

5 + 5 = 10 > 8

So one of the ordered pairs is (5, 5)

Therefore, the set of ordered pairs satisfying x + y > 8 = {(4, 5), (5, 4), (5, 5)}.

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Sets - Ordered Pairs
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Chapter 2: Relations and Functions - Exercise [Page 28]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 2 Relations and Functions
Exercise | Q 5.(iii) | Page 28

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