Given that A = `[(α,β),(γ,-α)]` and A2 = 3I, then:

3 − α2 − βγ = 0 Explanation: A2 = 3I `[(α^2+βγ,0),(0,βγ+α^2)] = [(3,0),(0,3)]` 3 − α2 − βγ = 0

English

Given that A = αβγα[αβγ-α] and A2 = 3I, then: -

Given that A = `[(α,β),(γ,-α)]` and A² = 3I, then:

MCQ

3 − α² − βγ = 0

Explanation:

A² = 3I

`[(α^2+βγ,0),(0,βγ+α^2)] = [(3,0),(0,3)]`

3 − α² − βγ = 0

shaalaa.com

Is there an error in this question or solution?

Notifications