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Question
Given, that `"E"_("O"_2//"H"_2"O")^circ` = + 1.23 V;
`"E"_("S"_2"O"_8^{2-}//"SO"_4^(2-))` = 2.05 V;
`"E"_("Br"_2//"Br")^circ` = 1.09 V;
`"E"_("Au"^{2+}//"Au")^circ` = + 1.4 V
The strongest oxidizing agent is:
Options
Au3+
O2
`"S"_2"O"_8^(2-)`
Br2
MCQ
Solution
`"S"_2"O"_8^(2-)`
Explanation:
As SRP `prop` oxidizing property. Here `"E"_("S"_2"O"_8^{2-}//"SO"_4^(2-))`, is highest, therefore it acts as strongest oxidizing agent.
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Classical Idea of Redox Reactions - Oxidation and Reduction Reactions
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